1.

Calculate the wavelength associated with an electron (mass 9.1 xx 10^(-31) kg) moving with a velocity of 10^3m sec^(-1) (h=6.626 xx 10^(-34) kg m^2 sec^(-1)) .

Answer»

Solution :Here we are given
`m = 9.1 XX 10^(-31) KG `
` V= 10^3m sec^(-1)`
`H = 6.626 xx 10^(-34) kg m^2 sec^(-1)`
`LAMDA =(h)/(mv) = (6.626 xx 10^(-34))/((9.1 xx 10^(-31) ) xx 10^3)`
`= 7.25 xx 10^(-7) m `


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