Calculate the VP of solution of 9g of glucose in162g of h2o at 293k

1.	Calculate the VP of solution of 9g of glucose in162g of h2o at 293k
Answer» The vapor pressure of the solution will be 17.45 mm of Hg Explanation : Given, weight of water = 162 g => NUMBER of moles of water, n₁ = 162/18 = 19 weight of glucose = 9 GM => number of moles of glucose, n₂ = 9/180 = 1/20 we know that vapor pressure of pure water at 293 k, P⁰ = 17.5 mm of Hg From RAOULT's law, (P⁰-P)/P⁰ = n₂/n₁ => 1 - P/P⁰ = 1/(20x19) => P/P⁰ = 379/380 = 0.99 => P = 17.5 x 0.99 = 17.45 mm of Hg Hence the vapor pressure of the solution will be 17.45 mm of Hg Read more on Brainly.in - brainly.in/question/15077548#readmore

Answer»

The vapor pressure of the solution will be 17.45 mm of Hg

Explanation :

Given,

weight of water = 162 g

=> NUMBER of moles of water, n₁ = 162/18 = 19

weight of glucose = 9 GM

=> number of moles of glucose, n₂ = 9/180 = 1/20

we know that vapor pressure of pure water at 293 k, P⁰ = 17.5 mm of Hg

From RAOULT's law,

(P⁰-P)/P⁰ = n₂/n₁

=> 1 - P/P⁰ = 1/(20x19)

=> P/P⁰ = 379/380 = 0.99

=> P = 17.5 x 0.99 = 17.45 mm of Hg

Hence the vapor pressure of the solution will be 17.45 mm of Hg

Read more on Brainly.in - brainly.in/question/15077548#readmore

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Calculate the VP of solution of 9g of glucose in162g of h2o at 293k

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