calculate the volumes of 2M and 5M of HCl solutions respectively to be

1.	calculate the volumes of 2M and 5M of HCl solutions respectively to be mixed to make 2L of 4M solution?
Answer» Total VOLUME of 4M HCL solution = 2 Litre consider volume of 5M HCl solution = ‘V’ Litre So, volume of 2M HCl solution = (2-V) Litre According to equation, (M1V1 + M2V2) / (V1+V2) = M3 M1 = 5M; V1 = V Litre M2 = 2M; V2 = (2-V) Litre M3 = 4M; V1+V2 = 2 Litre Substitute in equation, [5 X V + 2 x (2-V)] / 2 = 4 5V + 4 – 2V = 8 3V = 4 So, Volume of 5M HCl solution, V = 1.33 Litre Then, Volume of 2M HCl solution, 2-V = 2-1.33 = 0.67 Litre

calculate the volumes of 2M and 5M of HCl solutions respectively to be mixed to make 2L of 4M solution?

Answer»

Total VOLUME of 4M HCL solution = 2 Litre

consider volume of 5M HCl solution = ‘V’ Litre

So, volume of 2M HCl solution = (2-V) Litre

According to equation,

(M1V1 + M2V2) / (V1+V2) = M3

M1 = 5M; V1 = V Litre

M2 = 2M; V2 = (2-V) Litre

M3 = 4M; V1+V2 = 2 Litre

Substitute in equation,

[5 X V + 2 x (2-V)] / 2 = 4

5V + 4 – 2V = 8

3V = 4

So, Volume of 5M HCl solution, V = 1.33 Litre

Then, Volume of 2M HCl solution, 2-V = 2-1.33 = 0.67 Litre