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Calculate the volume of oxygen required for complete combustion of 20cm3 of ethane (C2H2) |
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Answer» don't know the equation equation is 2C2H2 + 5O2=4CO2 + 2H20. According to the gay lussac's law under the same conditions of TEMPERATURE and pressure gases occupy the same volume at the product and reactant side.2 MOLE of ethyne GAS occupies 20 cm cube of volume show ONE mole of ethyne gas occupies 10 centimetre cube volume. So 5 moles of oxygen occupies 20 x 5 that is 100 cm cube of volume.Done. Hope it helps |
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