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Calculate the volume of oxygen gas at STP liberatedby heating6. Calculat24.509of KC103 |
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Answer» The chemical equation for DECOMPOSITION of KClO 3 can be written as:2KClO 3 →2KCl+3O 2 245 G of KClO 3 GIVES 67.2 L of O 2 at STP.12.25 g of KClO 3 gives 24567.2 ×12.25 =3.36 L.Hence, option D is correct.Explanation:Hope it would help you. And please MARK it as brainliest and please FOLLOW me. |
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