1.

Calculate the volume of air containing 21% oxygen by volume at STP required to convert 294cm^(3) of sulphur dioxide to sulphur trioxide under the same conditions.

Answer»

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Solution :`underset(2xx27g)(2Al)+2NaOH+2H_(2)Orarr2NaAlO_(2)+underset(3xx22400"ML at STP")(3H_(2))`
`therefore""H_(2)" PRODUCED at STP from 0.15 g AL"=(3xx22400)/(54)xx0.15" mL = 186.7 mL"`
`underset("(STP conditions)")((P_(1)V_(1))/(T_(1)))=underset("(Required conditions)")((P_(2)V_(2))/(T_(2)))`
`"i.e.,"(1atmxx186.7mL)/(273K)=(0.987atm xxV_(2))/(293K)"(1 bar = 0.987 atm)"`
`"or"V_(2)=203.0mL`


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