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Calculate the volume of 80% (by mass) of H_2SO_4 (density = 1.80 g/mL] required to prepare 1 litre of 0.2 molar H_2SO_4 [Relative atomic masses : H = 1, O = 16, S = 32] |
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Answer» Solution :Applying the following relation and SUBSTITUTING the values, we get Molarity =`("PERCENTAGE by MASS x10 x d")/("molar mass") = (80 xx 10 xx 1.8)/(98) = 1440/98 = 14.69 "MOL" L^(-1)` Using molarity equation `M_1 V_1 = M_2V_2` `14.69 xx V_1= 0.2 xx 1000 mL` ` V_1 = (200)/(14.69) = 13.69 mL` Thus volume of `H_2SO_4` required = 13.6 mL |
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