1.

Calculate the volume occupied by 28u nitrogen gas​

Answer»

Answer:

3.71*10power-23L

Explanation:

molecular mass of NITROGEN =28u.

28u nitrogen GAS=1molecules of N

1mole of nitrogen gas at STP occupies=22.4L

that means6.023*10power23molecules of N occupies=22.4L

hence,28u occupies=22.4/6.023*10power23

=3.71*10power-23



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