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Calculate the volume occupied by 28u nitrogen gas |
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Answer» Answer: 3.71*10power-23L Explanation: molecular mass of NITROGEN =28u. 28u nitrogen GAS=1molecules of N 1mole of nitrogen gas at STP occupies=22.4L that means6.023*10power23molecules of N occupies=22.4L hence,28u occupies=22.4/6.023*10power23 =3.71*10power-23 |
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