Calculate the volume occupied by 10^22molecules of a gas at300Kand 760

1.	Calculate the volume occupied by 10^22molecules of a gas at300Kand 760mmpressure
Answer» A mole of substance contains 6×10^23 molecules,atoms or particles. No of moles containing 10^22 molecules = 10^22/6×10^23=1/60 = n . Pressure =760 mm of HG= 1atm=P. Temperature=300K=T. use the formula below to find the volume PV=nRT where V is the volume and R is the universal gas constant WHOSE value is 0.0821 atm litre /moles Kelvin. (1 )V=(1/60)(0.0821(300) => V=24.63/60=0.4105 litres =410.5 millilitres.hope it HELPS you.

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