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Calculate the voltage `E` of the cell `Ag(s) AgIO_(3)(s)|Ag^(+) (x,M), HIO_(3) (0.300M)||Zn^(2+) (0.175M)|Zn(s)` If `K_(SP) = 3.02 xx 10^(-8)` for `AgIO_(3)(s)` and `K_(a) = 0.162` for `HIO_(3), E^(@) (Zn^(+2)//Zn) =- 0.76 V, E^(@) (Ag//Ag^(+)) =- 0.8V` |
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Answer» Correct Answer - `-1.188V` `{:(HIO_(3),hArr,H^(+)+,IO_(3)^(-)),(C,,,),(C-X,,X,X):}` `0.162 =(x^(2))/(0.3 -x)` `x = 0.153` `K_(sp) = [Ag^(+)] [IO_(3)^(-)]` `[Ag^(+)] = 1.974 xx 10^(-7)` `E_(cell) = 0.8 +(0.76) -(0.0591)/(2)log. (|Ag^(+)|^(2))/([Zn^(2+)])` `E_(cell) - 1.188` |
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