1.

Calculate the viscosity of molecular oxygen in Pa s at 273 K and 1 bar. Given that molecular diameter = 0.36 xx 10^(-9) m, k = 1.38 xx 10^(-23) JK^(-1) and Av. const. = 6.022 xx 10^(23)

Answer»

Solution :Mass of one `O_(2)` MOLECULE, `m = (32 xx 10^(-3))/(6.022 xx 10^(23))`
`= 5.314 xx 10^(-26) KG`.
We have,
`eta = (5)/(16 SIGMA^(2))((m k T)/(pi))^(1//2)`
`= (5)/(16 xx (0.36 xx 10^(-9))^(2))((5.314 xx 10^(-26) xx 1.38 xx 10^(-23) xx 273)/(22//7))^(1//2)`
`= 1.926 xx 10^(-5)` Pa s.


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