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Calculate the velocity of an electron revolving in the second orbit of a hydrogen atom from the given data |
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Answer» SOLUTION :`v_(1)= 2.19 XX 10^(8) cm//s` We have, `v_(N)= (v_(1))/(n)` `therefore v_(2)= (2.19 xx 10^(8))/(2)` `=1.09 xx 10^(8) cm//s` |
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