1.

Calculate the velocity of an electron revolving in the second orbit of a hydrogen atom from the given data

Answer»

SOLUTION :`v_(1)= 2.19 XX 10^(8) cm//s`
We have, `v_(N)= (v_(1))/(n)`
`therefore v_(2)= (2.19 xx 10^(8))/(2)`
`=1.09 xx 10^(8) cm//s`


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