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Calculate the vapour pressure of aqueous 0.1m glucose solution at 300K temperature, the vapour pressure of water is 0.03 bar at 300K temperature.Solve the example. |
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Answer» Explanation:Quantity of glucose solution = 0.1 mol (Given)TEMPERATURE = 300k (Given)Vapour pressure of water = 0.03 bar (Given)THUS, N(glucose) = 0.1 molW (water) = 1 L = 1 kgn (water) = 1000/18 = 55.56 molMole fraction of the water -X(water) = 55.56 / (55.56 + 0.1) = 0.9998Vapour pressure of glucose solution is CALCULATED by -P(solution) = P°(water)x(water)= 0.03 × 0.9998= 0.02998 barTherefore, the vapour pressure of glucose soln is 0.02998 bar. |
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