1.

Calculate the van't Hoff factor of CdSO_(4) (molecular mass 208.4) if the dissolution of 5.21 g of CdSO_(4) in half litre water gives a depression in freezing point of 0.168^(@)C (K_(f) of water is "1.86 K kg mol"^(-1))

Answer»


Solution :`500cm^(3)H_(2)O=500g, i.e., w_(1)=500g,"MOLALITY (m) "=(5.21)/(208.4)xx(1000)/(500)=0.05`
`DeltaT_(f)"(calculated)"=K_(f)xxm=1.86xx0.05=0.093`
`DeltaT_(f)"(OBSERVED)"=0.168^(@)C""therefore""i=(0.168)/(0.093)=1.806""("orapply "DeltaT_(f)=eK_(f)m)`


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