1.

Calculate the value of log K_(3) when log values of K_(2),K_(1),K_(4) and K_(4) respectively are 2.0, 3.20, 4.0 and 11.9 ?

Answer»

`2.0`
2.7
3
2.5

Solution :`beta=K_(1)K_(2)K_(3)K_(4)`
LONG `beta=log(K_(1)K_(2)K_(3)K_(4))`
`logbeta=logK_(1)+logK_(2)+logK_(3)+logK_(4)`
`logK_(3)=11.9-(3.20+2.0+4.0)`
`logK_(3)=2.7`


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