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Calculate the value of Bohr magneton. For a hydrogen like atom with a 3d electron, what is the value of the orbital angular momentum in terms of h? (e=1.6 xx 10^(-19)c, h= 6.626 xx 10^(-34)J.s and m_(e)= 9.109 xx 10^(-31)kg)

Answer»

Solution :We have, `mu_(B) (BM)= (EH)/(4pi m)`
`= ((1.6 xx 10^(-19)) (6.626 xx 10^(-34)))/(4 xx 3.14 xx 9.109 xx 10^(-31))`
`=9.266 xx 10^(-24)JT^(-1)`
Further, we have
`L= sqrt(l(l+1)) (h)/(2pi) = sqrt(l(l+1))ħ`
For a 3d electron, l=2
`L= sqrt(2 (2+1))ħ= sqrt6ħ`


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