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Calculate the useful work of the reaction Ag(s)+`1//2Cl_2(g)to AgCl(s)` Given `E_(C l^(-)//C l^(-))^(@)=+1.36 V, E_(Ag|AgCl|Cl^(-))^(@)=0.22 V` If `P_(Cl_(2))`=1 atm and T=298 KA. 110 kJ/molB. `220 "kJ"//"mol"`C. `55 "kJ"//"mol"`D. `1000 "kJ"//"mol"` |
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Answer» Correct Answer - A `(1) AgCl(s)+e toAg(s)+Cl^(-) " " E^@=0.22 V` `(2)1//2Cl_2+e to Cl^(-) " " E^@=1.36 V` we get `Ag(s) + 1//2 Cl_2(g) to AgCl(s) " " E_("cell")^@=0.14 V` `therefore DeltaG=-nEF^@=-(1)(96500)(1.14)=-110` kJ/mol |
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