1.

Calculate the useful work of the reaction Ag(s)+1//2Cl_2(g)to AgCl(s) Given E_(C l^(-)//C l^(-))^(@)=+1.36 V, E_(Ag|AgCl|Cl^(-))^(@)=0.22 V If P_(Cl_(2))=1 atm and T=298 K

Answer»

110 kJ/mol
`220 "kJ"//"mol"`
`55 "kJ"//"mol"`
`1000 "kJ"//"mol"`

SOLUTION :`(1) AgCl(s)+e TOAG(s)+Cl^(-) " " E^@=0.22 V`
`(2)1//2Cl_2+e to Cl^(-) " " E^@=1.36 V`
we GET
`Ag(s) + 1//2 Cl_2(g) to AgCl(s) " " E_("cell")^@=0.14 V`
`therefore DeltaG=-nEF^@=-(1)(96500)(1.14)=-110` kJ/mol


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