1.

Calculate the U_("rms")" of "O_(2) if its density at 1 atm pressure and 0^(@)C is 1.4290 g " litre "^(-1)

Answer»

Solution :`U_("RMS") =sqrt((3P)/(d))`
In M.K.S : P=1 atm `=101.325 xx10^(3) PA,`
`d=1.4290" g/litre "=(1.4290xx10^(-3))/(10^(-3))kg//m^(3)=1.4290kg//m^(3)`
`therefore U_("rms") =sqrt((3xx101.325xx10^(3))/(1.4290))=461.21 m//sec`


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