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Calculate the total pressure in a mixture og `8 g` of oxygen and `4 g` hydrogen confined in a vessel of `1 dm^(3)` at `27^(@)C`. `(R = 0.083 "bar" dm^(3) K^(-1) mol^(-1))` |
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Answer» `W_(O_(2))=8 g` Moles of `O_(2)=8/32=1/4` `W_(H_(2))=4 g` Moles of `H_(2)=4/2=2` Total moles present in mixture `=1/4+2=9/4` Volume of vessel `=1 dm^(3)=1 L` Temperature `=27^(@)C=27+273=300 K` Now for pressure of mixture `=PxxV=nxxRT` `Pxx1=9/4xx0.083xx300` `P=56.025 "bar"` |
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