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Calculate the total pressure in a mixture of `4 g` of oxygen and `2 g` of hydrogen confined in a total volume of `1 L` at `0^(@)C`. |
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Answer» Correct Answer - `25.49 "bar"` No. of mass of oxygen `= ("Mass")/("Molar mass ") = 4/32 = 0.125 ` mol No. of moles of hydrogen `= ("Mass")/("Molar mass") = (2)/(2) = 1.0` mol Total no. of moles `= 0.125 + 1= 1.125` mol. According to ideal gas equation , `PV = nRT` `n = 1.125 mol, V = 1L, T = 0 + 273 = 273 K, R = 0.083 L "bar" K^(-1) mol^(-1)` `:. P = (nRT)/(V) = ((1.125 mol) xx (0.083 L "bar" K^(-1) mol^(-1)) (273K))/((1 L)) = 25.49 "bar"` |
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