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Calculate the total kinetic energy of the molecules of nitrogen per cm3 at STP and per m3 at STP. |
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Answer» 1 mole of a gas occupies 22400 cc at STP KE of 22,400 cc of a gas at STP = KE of 1 mole of a gas at STP = 3/2 x RT = 3/2 x 8.314 × 273 = 3404.58 J KE of 1 cc of a gas = 3404.58/22400 = 0.152 J KE of a m3 of a gas = 0.152 × 106 = 152 × 103 J. |
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