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Calculate the time taken for particele energy to drop to half its initial value in the case of a damped oscillator. |
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Answer» SOLUTION :We know that `E(t)=E(0)e^(-BT//m)` where`""E(0)=(1)/(2)KA^(2)` `"Given,"E(t)=(1)/(2)(E(0)),""therefore ""(1)/(2)=e^(-bt//m)=e^((1)/(bt//m))` `"i.e."e^(bt//m)=2""(bt)/(m)=2.303log 2=0.693` `t=(0.693m)/(B)` |
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