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Calculate the time in which a layer of ice 6 cm thick, on the surface of a pond will increase in thickness by 2 mm. Temperature of the surrounding air =-20^(@) "C" , L = 333 "KJ kg"^(-1) Conductivity of ice =0.08cal s−1cm−1∘C−1..

Answer»


Solution :`x=6 + 6.2 //2 = 6.1 xx 10^(-2) m, m L= KA ( theta_1 - theta_2) t// x, A xx 2 xx 10^(-3)xx 920 xx 333 xx 10^(3)= 2 A xx 20 t//6.1 xx 10^(-2) , t = 934.4` SECOND


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