1.

Calculate the tension in the thread during equilibrium condition(m=80×10^(-6)kg, q=2×10^(-8)C) -

Answer»

8.8 N
`8.8 xx 10^(2)N`
`8.8 xx 10^(-4)N`
`8.8 xx 10^(-3)N`

Solution :
during equilibrium
`T cos theta = MG`
`T sin theta = qE`
`T = sqrt((mg)^(2)+(qE)^(2))`
`T= sqrt((80xx10xx10^(-6))^(2)+(2xx10^(-8) xx 2 xx 10^(4))^(2))`
`T= sqrt(64 xx 10^(-8) +16 xx 10^(-8))`
`T= sqrt(80 xx 10^(-8)) = 8.8 xx 10^(-4)N`


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