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Calculate the temperature of 4.0 mol of a gas occupying d `dm^(3)` at 3.32 bar. (R=0.083 bar `dm^(3) K^(-1)mol^(-1))`. |
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Answer» Correct Answer - 50 K Given, n = 4.0 mol V= 5 `dm^(3)` p = 3.32 bar R= 0.083 bar `dm^(3)K^(-1)mol^(-1)` The temperature (T) can be calculated using the ideal gas question as: pV = nRT `rArrT=(pV)/(nR)` `=(3.32xx5)/(4xx0.083)` = 50 K Hence, the required temperature is 50 K. |
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