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Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K-1 mol-1) |
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Answer» Amount of the gas, n = 4.0 mol Volume of the gas, V = 5 dm3 Pressure of the gas, p = 3.32 bar R = 0.83 bar dm3 K-1 mol-1 From the gas equation, pV = nRT or, T = {pV}/{nR} = {3.32 bar x 5 dm3}/{4.0 mol x 0.083 bar dm3 K-1 mol-1} = 50 K |
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