1.

Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K-1 mol-1)

Answer»

Amount of the gas, n = 4.0 mol

Volume of the gas, V = 5 dm3

Pressure of the gas, p = 3.32 bar

R = 0.83 bar dm3 K-1 mol-1

From the gas equation,

pV = nRT

or, T = {pV}/{nR}

= {3.32 bar x 5 dm3}/{4.0 mol x 0.083 bar dm3 K-1 mol-1}

= 50 K



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