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Calculate the temperature of `4.0 mol` of a gas occupying `5 dm^(3)` at 3.32 bar. Strategy : List the variables with the proper units. Then solve the ideal gas equation for `T` by substituting the values. |
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Answer» `PV=nRT` `P=3.32 "bar", V=5 dm^(3)` `n=4 mol`, `R=0.083 "bar" dm^(3) K^(-1) mol^(-1)` Therefore `3.32xx5=4xx0.083xxT` or `T=(3.32xx5)/(4xx0.083)=50 K` |
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