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Calculate the temperature at which the root-mean-square speed of SO_(2) molecules is the same as that of oxygen at 27^(@)C. |
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Answer» Solution :We have, `C = SQRT((3RT_(SO_(2)))/(M_(SO_(2)))) = sqrt((3RT_(O_(2)))/(M_(O_(2))))` or `sqrt((3RT_(SO_(2)))/(64)) = sqrt((3R.300)/(32))` `T_(SO_(2)) = 600 K`. |
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