1.

Calculate the standard reduction potential of Ag^(+)|Ag electrode when the cellpotential for the cell , Cu (s) |Cu^(2+) (1 M) || Ag^(+) (1 M) Ag is 0.46 V . Given that Cu^(2+) |Cu = 0.34 V

Answer»


SOLUTION :`E_(Cell)^(THETA) = E_((Ag^(+) |Ag))^(Theta) - E_((Cu^(2+) |Cu))^(Theta)`
`0.46 = E_(Ag^(+) |Ag)^(Theta) = -0.34`
`THEREFORE E_((Ag^(+)|Ag))^(Theta) = 0.80 V`


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