1.

Calculate the standard heat of formation of carbon disulphide (l), given that the standard heat of combustion of carbon (s), sulphur (s) and carbon disulphide (l) are -393.3, -293.72and -1108.76 kJ mol^(-1) respectively

Answer»

`-128.02 KJ MOL^(-1)`
`+12.802 kJ mol^(-1)`
`+128.02 kJ mol^(-1)`
`-12.802 kJ mol^(-1)`

Solution :`C+2SrarrCS_(2) DeltaH=?`
`C+O_(2)rarrCO_(2)DeltaH=-393.3 kJ "....(i)"`
`S+O_(2)rarrSO_(2)DeltaH=-293.72 kJ "....(II)"`
`CS_(2)+3O_(2)rarrCO_(2)+2SO_(2) DeltaH=-1108.76 kJ"....(iii)"`
eq.(ii) `xx2+` eq. (i) - eq. (iii) - and find required RESULT.


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