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Calculate the standard cell potential ofgalvanic cell in which the following reactions take place :(Given E_(OP)^0 Cr,Cd,Fe^(2+),Ag are 0.74,0.40V, -0.77 and -0.80V respectively) Fe_((aq))^(2+)+Ag_((aq))^+ to Fe_((aq))^(3+)+Ag_((s)) |
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Answer» Solution :`E_("CELL")^0=E_(OP_(Fe^(2+)//Fe^(3+))^0+E_(RP_(Ag^+//Ag))^0` `[Fe^(2+)toFe^(3+)+E^-,Ag^+ +e toAg]` `=-0.77+0.80=0.03V` Also `-/_\_rG^0=nE^0F=1xx0.03xx96500` or `/_\_rG^0=-2895J` Also `-/_\_rG^0=2.303RT LOG K` 2895=`2.303xx8.314xx298 log K` K=3.22 |
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