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Calculate the ‘spin only’ magnetic moment ofM^(2+) (aq) ion (Atomic number Z of M= 27) |
Answer» Solution :ELECTRONIC configuration of `M=[Ar]3d^7 4s^2` Outer electronic configuration of `M^(2+)=3d^7` i.e. `THEREFORE` Number of unpaired electrons =3 `therefore` Spin only mangnetic MOMENT `sqrt(n(n+2))=sqrt(3(3+3))=sqrt(15)=3.87` BM 
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