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Calculate the spin only magnetic moment of Fe2+. |
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Answer» Fe2+ ion has electric configuration (Ar)4S03d6 it has four paired electrons ∴ n = 4 spin only magnetic moment μ = \(\sqrt{n(n+2)}BM\) = \(\sqrt{4(4+2)}BM\) = \(\sqrt{24}BM\) = 4.9BM |
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