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Calculate the spin - only magnetic moment of Fe [Atomic number of iron = 26]. |
Answer» Solution :`Fe=1s^(2)2s^(2)3s^(2)3P^(6)4s^(2)3D^(6)` `(i)mu=SQRT(N(n+2))` `=sqrt(4(4+2)=4.89B.M` |
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