1.

Calculate the spin - only magnetic moment of Fe [Atomic number of iron = 26].

Answer»

Solution :`Fe=1s^(2)2s^(2)3s^(2)3P^(6)4s^(2)3D^(6)`

`(i)mu=SQRT(N(n+2))`
`=sqrt(4(4+2)=4.89B.M`


Discussion

No Comment Found