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Calculate the specific rotation of coniine (the toxic component of poison hemlock), if a solution containing `0.75g `in `10 mL` is placed in a `1-dm` polarimeter tube and its observed rotation at `25^(@)C(D` line) is `+1.2^(@)`.A. `+1.6^(@)`B. `+16^(@)`C. `+3.2^(@)`D. `+32^(@)` |
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Answer» Correct Answer - B Specific rotation `= ("observed rotation"(degress))/("length"(dm)xx "concetration or density" (g//mL^(-1)))` `[alpha]_(D)^(25^(@)) = (+1.2^(@))/((1)(0.75)/(10))=+16^(@)` Note that the specific rotation of the enantiomer of coniine is `-16^(@)` Also note that the specific rotation is a constant and is independent of concetration and path length. |
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