1.

Calculate the specific resistance of a 0.02 N solution of an electrolyte having equivalent conductance 103 ohm^(-1)cm^(2) (g eq.)^(-1).

Answer»


Solution :`Delta_(E)=(1000xxk)/(C )or k=(Delta_(E)XXC)/(1000)`
`Delta_(E)=103" ohm"^(-1)cm^(2)(G eq)^(-1),C=0.02" N"`
`:."" k=(103" ohm"^(-1)cm^(2) cm^(-1)("g eq")^(-1)xx0.02("g eq"))/((1000" cm"^(3)))=2.06xx10^(-3)" ohm^(-1)cm^(=-1)`
Specific RESISTANCE `(rho)=(1)/(k)=(1)/(2.06xx10^(-3) ohm^(-1) cm^(-1))=485.4" ohm " cm`.


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