Calculate the solubility product of the sparingly soluble salt CaF2 from the following data:The molar ionic conductances (at infinite dilution) of Ca2+ and F− ions are 104×10−4 and 48×10−4Sm2mol−1respectively. The specific conductance of the saturated solution of CaF2 at room temperature is 4.25×10−3Sm−1 and the specific conductance of water used for preparing the solution is 2×10−4Sm−1.

Calculate the solubility product of the sparingly soluble salt CaF2 fr

1.	Calculate the solubility product of the sparingly soluble salt CaF2 from the following data:The molar ionic conductances (at infinite dilution) of Ca2+ and F− ions are 104×10−4 and 48×10−4Sm2mol−1respectively. The specific conductance of the saturated solution of CaF2 at room temperature is 4.25×10−3Sm−1 and the specific conductance of water used for preparing the solution is 2×10−4Sm−1.
Answer» Calculate the solubility product of the sparingly soluble salt $C a F_{2}$ from the following data: The molar ionic conductances (at infinite dilution) of $C a^{2 +}$ and $F^{-}$ ions are $104 \times 10^{- 4}$ and $48 \times 10^{- 4} S m^{2} m o l^{- 1}$ respectively. The specific conductance of the saturated solution of $C a F_{2}$ at room temperature is $4.25 \times 10^{- 3} S m^{- 1}$ and the specific conductance of water used for preparing the solution is $2 \times 10^{- 4} S m^{- 1}$ .