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| 1. |
Calculate the solubility product of the reactionFe(OH)_3 = Fe^(3+)+ 3OH^(-)Given that Fe(OH)_3(s)+ 3e = Fe(s) + 3OH^(-) , E^@ =-0.77VFe^(3+) + 3e = Fe(s) E^@ = -0.036V |
| Answer» SOLUTION :`8.699 XX 10^(-38)` | |