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Calculate the solubility product of `PbCl_(2)` at a certain temperature if the solubility of `PbCl_(2)` is 4.4 g/L at the same temperature. `(Pb=207,Cl=35.5)` |
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Answer» Molar concentration of `PbCl_(2)=1.6xx10^(-2)M` `"[Concentration of"PbCl_(2)=4.4g//L=(4.4)/(278)=1.6xx10^(-2)mol//L"]"` `PbCl_(2)hArrPb^(+2)+2Cl` `{:(1,0,0),(1-s,s,2s):}` `K_(sp)=[Pb^(+2)][Cl^(-)]^(2)` `=sxx(2x)^(2)=4s^(3)` `=(1.6xx10^(-2))xx4=1.63xx10^(-5)` |
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