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Calculate the solubility of H2 in water at 25 degree celsius if its partial pressure above the solution is 1 bar. given that henry's constant for H2 in water at 25 degree celsius is 71.18 kbar. need the answer very urgentlyy!! |
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Answer» law states that : where p = partial pressure of the gas above the solution. is the Henry's solubility constant for the solvent & solute at given T°C c = molar CONCENTRATION of the solute in the solution in moles/Litre at given T°Cp = 1 BAR and =71.18 kbar-Litre/mol c = 1 / 71.18 * 10³ = 14.048 mol/Litre concentration = 14.048 mol/Litre or 28.096 gms/Litre |
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