1.

Calculate the solubility of A2X3 pure water, Assuming that neither king of ion reacts with water. The solubility product of A2X3 Ksp = 1.1 × 10-23. Explain with equation.

Answer»

ksp = [A3+]2 [X-2]3 = [2s]2 [3s]3 =108 s5 

S5 = 1.1 x 10-23/108 = 1 × 10-25 

S5 = 1 × 10-5 mol dm-3



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