1.

Calculate the safe speed with which a train can negotiate a curve of 50 m radius, where the superelevation of the outer rail above the inner rail is 0.6 m. Given that the distance between the rails is 1 m

Answer»


SOLUTION :`V = SQRT(hrg//l) = sqrt(0.6 XX 50 xx 9.8//1) = 17.14 m//s`


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