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Calculate the resulting molarity of the solution that is obtained by adding 5 g of NaOH to 250 ml of (M)/(4)NaOH solutoin (density =1.05 g//cm^(3)). The density of the resulting solutoin is 1.08 g//cm^(3). |
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Answer» Solution :`"250 ml of "(M)/(4)" NaOH CONTAINS "=(40)/(4)xx(250)/(1000)g="2.5 g NaOH"` `"250 ml of NaOH sol "=250xx1.05g=262.5g` After ADDING 5g NaOH, now solute = 7.5 g and solution = 267.5 g VOLUME of NEW solution `=(267.5)/(1.08)=247.7ml=0.2477L` Molarity `=(7.5)/(40)molxx(1)/(0.2477L)=0.76M.` |
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