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Calculate the resonance energy of 1,3-butadiene from the following data- CH_3CH_2CH=CH_2+H_2overset(Pt)toCH_3CH_2CH_3 DeltaH=-30 kcal.mol^(-1) CH_2=CH-CH=CH_2+2H_2overset(Pt)toCH_3CH_2CH_2CH_3 DeltaH=-57kcal.mol^(-1) |
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Answer» SOLUTION :Heat liberated due to HYDROGENATION of one DOUBLE bond = 30 kcal `mol^(-1)`. `:.` Heat liberated due to hydrogenation of TWO double bonds `= 30 xx 2 = 60 kcal mol^(-1)`. Heat liberated due to hydrogenation of 1, 3-butadiene `(CH_(2)=CH - CH = CH_(2)) = 57 kcal mol^(-1)` Therefore, resonance energy of 1,3-butadiene `60 -57 = 3 kcal. mol^(-1)` |
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