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Calculate the ratio of concentration of HCOO^(-) & OCN^(-) ions in a solution containing 0.1MHCOOH (K_(a)=1.8xx10^(-4)) and 0.1MHOCN(K_(a_(1))=4xx10^(-4)) .if simplest ratio is a:b reprot your answer as (a+b). |
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Answer» Solution :`[H^(+)]` is the same for equilibria of both acids. Now ,let `[HCOO^(-)]=aM` and `[OCN^(-)]=b M` `:.([H^(+)]XXA)/(0.1)=1.8xx10^(-4)&([H^(+)]xxb)/(0.1)=4XX10^(-4)rArr (a)/(b)=(9)/(20)` So `(a+b)=29` |
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