Calculate the ratio of atoms present in 5g of magnesium and 5g of iron

1.	Calculate the ratio of atoms present in 5g of magnesium and 5g of iron.[atomic mass of Mg=24u,Fe=56u]
Answer» Answer: 7:3 Explanation: No of ATOMS=No. of MOLES × atomicity × N(6.02×10^23) No. of MG atoms = (5/24)×1×N No. of Fe atoms= (5/56)×1×N ratio(Mg:Fe)= (5/24)×1×N/ (5/56)×1×N =7/3 hence answer is 7:3

Calculate the ratio of atoms present in 5g of magnesium and 5g of iron.[atomic mass of Mg=24u,Fe=56u]

Answer»

Answer:

7:3

Explanation:

No of ATOMS=No. of MOLES × atomicity × N(6.02×10^23)

No. of MG atoms = (5/24)×1×N

No. of Fe atoms= (5/56)×1×N

ratio(Mg:Fe)= (5/24)×1×N/ (5/56)×1×N

=7/3

hence answer is 7:3