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Calculate the rate constant of a reaction (first order) which is 90% complete in 10 min. |
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Answer» SOLUTION :Rate CONSTANT. `lambda=2.303/t(LOG)(100)/(100-90)=[2.303/10xx(log)100/10]min^-1=[2.303/10xx(log)10]min^-1` .`=0.2303min^-1` |
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