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Calculate the range of the variable capacitor that is to be used in a tuned-collector oscillator which has a fixed inductance of 150 pH.The frequency band is from 500 KHz to 1500KHz. |
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Answer» Solution :Resonant frequency `f_(0) =1/(2PI sqrt(LC))` On simplifying we GET `C = 1/(4pi^(2)f_(0)^(2)L)` When frequency is equal to 500 kJz `C = 1/(4 xx 3.14^(2) xx (500 xx 10^(3))^(2) xx 150 xx 10^(-6)) = 676 pF` When frequency is equal to 1500 kHz `C = 1/(4 xx 3.14 xx (1500 xx 10^(3))^(2) xx 150 xx 10^(-6)) = 75 pF` Therefore, the capacitor range is 75 - 676 pF |
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