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Calculate the radius of the first Bohr orbit of a hydrogen atom. Given that h= 6.63 xx 10^(-27) erg.s, m= 9 xx 10^(-28)g and charge of an electron =4.8 xx 10^(-10) esu

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SOLUTION :We have for hydrogen, Z=1, n=1
`r_(1)= (H^(2))/(4pi^(2) m e^(2))`
`= ((6.63 xx 10^(-27))^(2))/(4 xx (3.14)^(2) xx 9 xx 10^(-28) xx (4.8 xx 10^(10))^(2))`
`=0.53xx 10^(-8) CM= 0.53 Å`


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